SOLUTION: One number is 4 more than another. The difference between their squares is 104. What are the numbers?
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Question 1049827: One number is 4 more than another. The difference between their squares is 104. What are the numbers?
Found 3 solutions by josgarithmetic, MathLover1, addingup:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Assign variables and translate the description literally.
Numbers are x and x+4.
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
let one number be and another
if one number is more than another, means
........eq.1
if the difference between their squares is , means
........eq.2
substitute from eq.1 in eq.2
........eq.2......solve for
now find
........eq.1
so, one number is and another
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
Let the numbers be x and y
x = y+4
x^2-y^2 = 104 Substitute for x:
(y+4)^2-y^2 = 104
Expand the left side with FOIL (First-Outer-Inner-Last)
(y^2+8y+16)-y^2 = 104
8y+(y^2-y^2)+16 = 104
8y+16 = 104
8y = 88
y = 11
Since x = y+4 = x = 11+4= 15
Now we have:
y = 11
x = 15
>>>>>>>>>>>>>>>>
Check:
x^2-y^2 = 104
15^2-11^2 = 104
225-121 = 104 Correct
:
John
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