SOLUTION: On a 3 positive consecutive integer the middle number is p. If 3 times the square of the largest number is greater than the sum of the other2 number by 67 find the value of p

Question 1047994: On a 3 positive consecutive integer the middle number is p. If 3 times the square of the largest number is greater than the sum of the other2 number by 67 find the value of p

Found 2 solutions by Horlaye, ikleyn:
Answer by Horlaye(27) (Show Source): You can put this solution on YOUR website!
Let the numbers be p-1, p, p+1
from the sentence
3(p+1) - (p-1+p) = 67
3p + 3 - p + 1 - p = 67
p = 67 - 4
p = 63
Answer by ikleyn(52914) (Show Source): You can put this solution on YOUR website!
.
On a 3 positive consecutive integer the middle number is p. If 3 times the square of the largest number is greater
than the sum of the other 2 number by 67 find the value of p
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

So, the numbers are p-1, p, and p+1. The condition says - ((p-1) + p) = 67. Simplify = 67, = 67, = 0. There is no solution in integer numbers.

Answer. There is no solution in integer numbers.

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