SOLUTION: The product of two numbers is 48. The first number is negative, and the second number is four more than twice the first number. Find the two numbers.

Question 1043558: The product of two numbers is 48. The first number is negative, and the second number is four more than twice the first number. Find the two numbers.

Found 2 solutions by josgarithmetic, stanbon:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
The product of two numbers is 48. The first number is negative,...
...then both of the numbers are negative!!

and we must take the NEGATIVE SOLUTION VALUE, according to the description.

We must also have a value from y according to the described system, listed at the top.

-----which also is consistent with the other equation.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The product of two numbers is 48. The first number is negative, and the second number is four more than twice the first number. Find the two numbers.
---------
x*y = 48
y = 2x+4
-----
x(2x+4) = 48
2x^2 + 4x - 48 = 0
x^2 + 2x - 24 = 0
----
(x+6)(x-4) = 0
x = -6
y = 2x+4 = -12+4 = -8
--------------------------------
Cheers,
Stan H.
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