SOLUTION: Find two positive numbers whose squares have a sum of 58 and a difference of 40

SOLUTION: Find two positive numbers whose squares have a sum of 58 and a difference of 40

Algebra.Com

Question 1033435: Find two positive numbers whose squares have a sum of 58 and a difference of 40
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
By the terms of the question, we have:
x^2+y^2=58
x^2-y^2=40;
If we add these two together, we get:
2x^2=98
x^2=49
x=7
y=3;
Checking, we get:
49+9=59
49-9=40!!!!!!!!!!!!

RELATED QUESTIONS
find two positive numbers whose squares have a sum of 25 and a difference of... (answered by farohw)

find two positive numbers whose squares have the sum of 85 and difference of... (answered by oberobic)

find 2 positive numbers whoes squares have a sum of 113 and a difference of... (answered by stanbon)

The difference of two positive numbers is 4 and the sum of their squares is 40. Find the... (answered by htmentor)

find two positive numbers whose sum is 324 and the sum of those squares is a... (answered by Fombitz)

Find two positive numbers which have a difference of 5 and whose product is... (answered by Alan3354)

Find two numbers whose sum is 23 and the difference of whose squares is... (answered by mducky2)

translate this word problem as a system of equations and then solve using... (answered by checkley79)

Translate this word problem as a system of equations and then solve using substitution. (answered by Fombitz)