SOLUTION: One number is 4 times as large as another. The sum of their reciprocals is 35/4. Find the two numbers.
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Question 1033309: One number is 4 times as large as another. The sum of their reciprocals is 35/4. Find the two numbers.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
One number is 4 times as large as another. The sum of their reciprocals is 35/4. Find the two numbers.
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a = 4b
(1/a) + (1/b) = 35/4
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Substitute for "a" and solve for "b"::
1/(4b) + 1/b = 35/4
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Multiply thru by 4b to get:
1 + 4 = 35b
b = 5/35 = 1/7
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a = 4b = 4/7
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Cheers,
Stan H.
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