SOLUTION: Two numbers that when subtracted are equal to fourteen and when doubled are equal to 130

Question 1033016: Two numbers that when subtracted are equal to fourteen and when doubled are equal to 130
Found 2 solutions by macston, Cromlix:
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
L=larger number; S=smaller number
.
L-S=14
L=S+14 . Use this to substitute for L below
.
2(L+S)=130
L+S=65 . Substitute for L from above
(S+14)+S=65
2S=51
S=25.5
.
L=S+14=25.5+14=39.5
.
ANSWER: The smaller number is 25.5 and the larger number is 39.5.

Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
Two numbers that when subtracted
are equal to fourteen.
x - y = 14........(1)
x = 14 + y........(1)
when doubled are equal to 130
2x + 2y = 130.....(2)
Substitute (14 + y) for x
in Eq(2)
2x + 2y = 130.....(2)
2(14 + y) + 2y = 130
28 + 2y + 2y = 130
Collect like terms:
2y + 2y = 130 - 28
4y = 102
y = 25 1/2
Substitute y = 25 1/2
into Eq(1)
x - 25 1/2 = 14
x = 14 + 25 1/2
x = 39 1/2
x = 39 1/2
y = 25 1/2
Hope this helps :-)

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