SOLUTION: The sum of three consecutive odd numbers
is 63. What is the smallest of these
numbers?
Algebra.Com
Question 1029645: The sum of three consecutive odd numbers
is 63. What is the smallest of these
numbers?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the numbers, x, x+2, and x+4.
Then we write
x + x+2 + x+4 = 63
3x + 6 = 63
Subtract 6 and then divide by three and get
3x = 57
x = 19 (the smallest number)
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