SOLUTION: Hi everyone, please can you help me with a maths problem: I am a odd 3 digit number, that is equal to another number multiplied by itself. the sum of my digits is 16. what number

Question 1024875: Hi everyone, please can you help me with a maths problem: I am a odd 3 digit number, that is equal to another number multiplied by itself. the sum of my digits is 16. what number am i.
Thanks!!!
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The number that is multiplied by itself can't be a
1-digit number. It can't be a 3-digit number, so
it must be a 2-digit number.
-------------------------
Also, the units digit must be odd since
( odd )x( odd) = odd in order to make odd
-------------------------
It can't be as large as , since
I could be as large as , since
It could be as small as , since
-------------------------
So, the possible numbers and their squares are:
11 - 121
13 - 169
15 - 225
17 - 289
19 - 361
21 - 441
23 - 529
25 - 625
27 - 729
29 - 841
31 - 961
---------
The sum of the digits of is
The sum of the digits of is
The sum of the digits of is
----------
I think the number can be
169, 529, or 961
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