SOLUTION: Ten times the smallest of three consecutive integers is twenty-two mire than three times the sum of the integers

Question 1024615: Ten times the smallest of three consecutive integers is twenty-two mire than three times the sum of the integers
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Ten times the smallest of three consecutive integers is twenty-two more than three times the sum of the integers:
10x = 3(x + (x+1) + (x+2)) + 22
10x = 3(3x + 3) + 22
10x = 9x + 9 + 22
10x - 9x = 31
x = 31 one is the smallest integer
:
:
See if this checks out
10(31) = 3(31+32+33) + 22
310 = 3(96) + 22
310 = 288 + 22
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