SOLUTION: given four consecutive odd numbers. when the square of the second number is subtracted from the product of the first and last numbers, the answer is 14. find them
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Question 1021817: given four consecutive odd numbers. when the square of the second number is subtracted from the product of the first and last numbers, the answer is 14. find them
Found 2 solutions by jorel555, josgarithmetic:
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let n be your first number. Then the next numbers would be: n+2,n+4, and n+6. So
(n)(n+6)-(n+2)²=14
n²+6n-n²-4n-4=14
2n=18
n=9
Your numbers are 9,11,13,and 15!!!!!!!!!!!!!!!
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
Numbers x-3, x-1, x+1, x+3
According to described,
The values are 9, 11, 13, 15.
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