SOLUTION: Find two consecutive integers such that the larger is nine more than twice the smaller

Question 1018609: Find two consecutive integers such that the larger is nine more than twice the smaller
Answer by toddcarnes(6) (Show Source): You can put this solution on YOUR website!
Question: Find two consecutive integers such that the larger is nine more than twice the smaller.
Answer:
Let x be your first integer.
Then x + 1 will be the next consecutive integer.
Create the equation given in the original problem...
(x+1) = 2x + 9
Solve for x...
x + 1 = 2x + 9
1 = x + 9
x = -8
If x = -8, then (x+1) = -7.
Therefore the two consecutive integers you are looking for are -8 and -7.
RELATED QUESTIONS
find two consecutive integers such that the larger is nine more than twice the smaller. (answered by JulietG)

find 2 consecutive integers such that the larger is nine more than twice the... (answered by lynnlo,MathTherapy)

Find two consecutive integers such that twice the smaller is two more than the... (answered by CubeyThePenguin)

Find two consecutive odd integers such that twice the larger is 17 more than the... (answered by QH)

Find two consecutive odd integers such that twice the larger is 17 more than the... (answered by mananth)

Find two consecutive integers such that twice the smaller is 16 more than the... (answered by ad_alta)

Find two consecutive even integers such that twice the smaller is 10 more than the larger (answered by fractalier)

Find two consecutive even integers such that twice the smaller is 16 more than the... (answered by jorel1380)

Find two consecutive even integers such that three times the smaller is 30 more than... (answered by richwmiller,Fombitz)