In problems like this, sometimes you can just guess them. But if you can't, then do it this way: x = first even integer x+2 = second even integer x(x+2) = 120 x² + 2x = 120 x² + 2x - 120 = 0a=1, b=2, c=-120 Using the + So one solution is x = 10 = first even integer x+2 = 10+2 = 12 = second even integer Using the - So another solution is x = -12 = first even integer x+2 = -12+2 = -10 = second even integer Edwin
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