SOLUTION: The sum of two numbers is 11. Three times the larger minus 2 times the smaller equals 8
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Question 1013809: The sum of two numbers is 11. Three times the larger minus 2 times the smaller equals 8
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the larger and the smaller, x and y. Then we have
x + y = 11 (or x = 11 - y)
and
3x - 2y = 8
Now substitute and get
3(11-y) - 2y = 8
33 - 3y - 2y = 8
-5y + 33 = 8
-5y = -25
y = 5
x = 6
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