SOLUTION: the sum of two numbers is 7 times their difference. the difference of their squares is twice their sum. find the numbers.
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Question 1012475: the sum of two numbers is 7 times their difference. the difference of their squares is twice their sum. find the numbers.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
the sum of two numbers is 7 times their difference.
a + b = 7(a-b)
a + b = 7a - 7b
b + 7b = 7a - a
8b = 6a
simplify, divide by 2
4b = 3a
b = 3a/4
b = .75a
:
the difference of their squares is twice their sum.
a^2 - b^2 = 2(a + b)
a^2 - b^2 = 2a + 2b
substitute for b
a^2 - (.75a)^2 = 2a + 2(.75a)
a^2 - .5625a^2 = 2a + 1.5a
Divide equation by a
a - .5625a = 2 + 1.5
.4375a = 3.5
a = 3.5/.4375
a = 8
Find b
b = .75(8)
b = 6
:
find the numbers. 8 & 6
:
:
:
See if this checks out
8 + 6 = 7(8 - 6)
14 = 7(2)
and
8^2 - 6^2 = 2(8+6)
64 - 36 = 2(14)
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