SOLUTION: find three consecutive integers such that twice the smallest plus three times the middle is equal to twenty-two less than six times the largest

Question 1011955: find three consecutive integers such that twice the smallest plus three times the middle is equal to twenty-two less than six times the largest
Found 2 solutions by Boreal, stanbon:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Let the integers be x, x+1, and x+2.
2x+3(x+1)=6(x+2)-22
2x+3x+3=6x+12-22
5x+3=6x-10
x=13
the numbers are 13,14,15
12*2=26
3*14=42
(6*15)-22=68.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find three consecutive integers such that twice the smallest plus three times the middle is equal to twenty-two less than six times the largest
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1st: x-1
2nd: x
3rd: x+1
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Equation:
2(x-1) + 3x = 6(x+1)-22
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2x - 2 + 3x = 6x + 6 - 22
5x -2 = 6x - 16
x = 14
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x-1 = 13
x = 14
x+1 = 15
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Cheers,
Stan H.
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