SOLUTION: twice one number is 15 less than a second number. when 13 is added to the second number, the result is 7 less than 9 times the first number. find the numbers.

Question 1009617: twice one number is 15 less than a second number. when 13 is added to the second number, the result is 7 less than 9 times the first number. find the numbers.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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F=first number; S=second number
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2F+15=S
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S+13=9F-7
(2F+15)+13=9F-7
2F+35=9F
35=7F
5=F
ANSWER 1: The first number is 5.
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S=2F+15=2(5)+15=10+15=25
ANSWER 2: The second number is 25.
.
CHECK:
S+13=9F-7
25+13=9(5)-7
38=45-7
38=38

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