SOLUTION: One positive integer is 3 less than twice another. The sum of their squares is 698. Find the integers.

Question 1008836: One positive integer is
3 less than twice another. The sum of their squares is
698. Find the integers.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
One positive integer is 3 less than twice another. The sum of their squares is
698. Find the integers.
----
x^2 + (2x-3)^2 = 698
5x^2 - 12x - 689 = 0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=13924 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 13, -10.6. Here's your graph:

==========
--> 13 & 23

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