SOLUTION: Find three consecutive numbers, that if you times the first number by two and then add the last number together it would equal 47. e.g. (((2a+c = 47)))

Question 1006944: Find three consecutive numbers, that if you times the first number by two and then add the last number together it would equal 47.
e.g.
(((2a+c = 47)))
Found 2 solutions by emsarj, Alan3354:
Answer by emsarj(1) (Show Source): You can put this solution on YOUR website!
hello, the answer would be 15,16,17.
15 times two would be 30. Add 17 to 30 is 47 which would all be correct according to your question!
A way to solve questions like these is the trial and error method. for example realistically the number would have to be under 20 but above 10 and then you may try 15 and see if it would be higher or lower.
Anyway I hope this helps and just to clarify the three answers would be 15,16,17!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find three consecutive numbers, that if you times the first number by two and then add the last number together it would equal 47.
e.g.
(((2a+c = 47)))
-----------
You can use n, n+1 & n+2
--> 2n + n+2 = 47
3n = 45
n = 15
--> 15, 16, 17
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