SOLUTION: The sum of three numbers is
106
. The first number is
8
less than the second. The third number is
4
times the second. What are the numbers?
Algebra.Com
Question 1002908: The sum of three numbers is
106
. The first number is
8
less than the second. The third number is
4
times the second. What are the numbers?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The sum of three numbers is
106
. The first number is
8
less than the second. The third number is
4
times the second. What are the numbers?
-----
Equations:
a + b + c = 106
a = b-8
c = 4b
--------------
Substitute for a and c; solve for "b"::
b-8 + b + 4b = 106
6b = 114
----
b = 19
----
a = b-8 = 11
-----
c = 4b = 76
------------------
Cheers,
Stan H.
-------------
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