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Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts
Problem 1A coffee shop has coffee which worth $6 per pound. They want to mix it with 20 pounds of coffee which worth $9 per pound to get
a mixture that can be sold for $8 per pound. How many pounds of the cheaper coffee should they use?
Solution
Let x be the number of pounds of coffee worth $6 per pound what should be mixed. It costs 6*x dollars.
20 pounds of $9 coffee costs 9*20 dollars. In total, the mix costs 6x + 9*20 dollars.
Hence, one pound of the mix costs . Thus you have an equation to determine x
= .
Simplify and solve it:
6x + 180 = 7*(x+20), (after multiplying both sides by (x+20) )
6x + 180 = 7x + 140,
180 - 140 = 7x - 6x,
40 = x.
Answer. x = 40. 40 pounds of the $6 coffee should be mixed with 20 pounds of $9 coffee to get the mix at the price of $7 per pound.
Problem 2Chocolate coffee beans sell for $7.00 per pound and hazelnut coffee beans sell for $6.10 per pound. One customer wants
a 6 pound mixture of both types of coffee. How many pounds of each should be used if the mixture is to cost $6.40 per pound?
Solution
Let c be the number of pounds of the chocolate coffee and h be the number of pounds of the hazelnut coffee to be mixed.
So, your first equation is:
c + h = 6
The cost of the mix should be 6*$6.40 = $38.40. From the other side, it is 7*c + 6.10*h. Thus you have the second equation
7*c + 6.10*h = 38.4.
Now, you can solve this system of two equations by substitution.
c = 6 - h,
7(6-h) + 6.1h = 38.4,
42 - 7h + 6.1h = 38.4,
42 - 0.9h = 38.4,
-0.9h = -3.6,
h = 4.
c + 4 = 6.
c = 2.
Answer. 2 pounds of chocolate coffee and 4 pounds of hazelnut coffee should be used.
Problem 3A customer has asked a caterer for 60 LB of nuts, 60% of which are to be cashews.
The caterer has available mixtures of 70% cashews and 45% cashews. How many pounds of each mixture should be used?
Solution
The caterer needs to mix x lbs of the 70% cashew mixture with (60-x) lbs of the 45% cashew mixture to obtain the 60 lbs of 60% cashew mixture.
Change the percentages to their decimal equivalents and write the algebraic equation to solve for x.
0.7*x + 0.45*(60-x) = 0.6*60.
Simplify and solve for x.
0.7x + 27 - 0.45x = 36.
Combine like-terms.
0.25x = 36-27,
0.25x = 9.
Divide both sides by 0.25.
x = 36.
Answer. The caterer should mix 36 lbs of the 70% cashew mixture with (60-36 = 24) lbs of the 45% cashew mixture to obtain 60 lbs of 60% cashew mixture.
Problem 4Peanuts sell for $3.00 per pound. Cashews sell for $6.00 per pound. How many pounds of cashews should be mixed
with 12 pounds of peanuts to obtain a mixture that sells for $4.20 per pound?
Solution
Let x be the number of pounds of cashews to be mixed.
So, the weight of the mix is 12 + x pounds.
The cost of the mix should be 12*$4.20 = $50.40. From the other side, it is 12*3 + 6.00*x dollars. Thus you have an equation
12*3 + 6.00*x = 50.40.
Simplify and solve the equation:
6x =50.40 - 36,
6x = 14.40,
x = = 2.4.
Answer. 2.4 pounds of cashews should be used.
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