SOLUTION: You have two beakers of acid solutions. One beaker contains a 25% acid solution, and the other beaker contains a 98% acid solution. How many liters of the 25% acid solution must

Question 999641: You have two beakers of acid solutions. One beaker contains a 25% acid solution, and the other beaker contains a 98% acid solution. How many liters of the 25% acid solution must you mix with the 98% acid solution to make 2 liters of a 63% acid solution? Write your answer correct to two decimal places
Found 2 solutions by jorel555, ikleyn:
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let the 98% acid solution be n. Then:
.98(n)+.25(2-n)=.63(2)
.98n+.5-.25n=1.26
.73n=.76
n=1.041 liters of 98% solution
2-n=.959 liters of 25% solution ☺☺☺☺
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
You have two beakers of acid solutions. One beaker contains a 25% acid solution, and the other beaker contains a 98% acid solution.
How many liters of the 25% acid solution must you mix with the 98% acid solution to make 2 liters of a 63% acid solution?
Write your answer correct to two decimal places
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

25% in the input and 25% in the output?

If your numbers are correct, then only 25% acid should be used at the amount of 2 liters.

98% acid should not be used at all.

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