SOLUTION: How much of a 12% saline solution should be mixed with a 4% saline solution to obtain 40 milliliters of a 6% saline solution? Use a system of equations and the elimination method t

Question 995463: How much of a 12% saline solution should be mixed with a 4% saline solution to obtain 40 milliliters of a 6% saline solution? Use a system of equations and the elimination method to solve the problem.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How much of a 12% saline solution should be mixed with a 4% saline solution to obtain 40 milliliters of a 6% saline solution? Use a system of equations and the elimination method to solve the problem.
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Quantity:: t + f = 40 ml
Active:::0.12t+0.04f = 0.06*40
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Modify for elimination:
4t + 4f = 4*40
12t + 4f = 6*40
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Subtract and solve for "t"::
8t = 2*40
t = 10 ml (amt of 12% solution needed)
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Cheers,
Stan H.
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