SOLUTION: how many liters of a 20% solution of a chemical should be mixed with 10 liters of a 50% solution to obtain a mixture that is 40% chemical
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Question 994364: how many liters of a 20% solution of a chemical should be mixed with 10 liters of a 50% solution to obtain a mixture that is 40% chemical
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how many liters of a 20% solution of a chemical should be mixed with 10 liters of a 50% solution to obtain a mixture that is 40% chemical
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Equation:
active + active = active
0.20x + 0.50*10 = 0.40(x+10)
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20x + 50*10 = 40x + 40*10
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-20x = -10*10
x = 5 liters (amt. of 20% solution needed)
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Cheers,
Stan H.
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