SOLUTION: How many liters of a 20% acid solution must be mixed with a 50 % acid solution in order to obtain 12 liters of a 30% solution?
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Question 990201: How many liters of a 20% acid solution must be mixed with a 50 % acid solution in order to obtain 12 liters of a 30% solution?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many liters of a 20% acid solution must be mixed with a 50 % acid solution in order to obtain 12 liters of a 30% solution?
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Equation:
acid + acid = acid
0.50x + 0.20(12-x) = 0.30*12
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50x + 20*12 - 20x = 30*12
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30x = 10*12
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x = (1/3)12 = 4 liters (amt. of 50% solution needed)
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12-x = 8 liters (amt. of 20% solution needed)
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Cheers,
Stan H.
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