SOLUTION: Factors the polynomial P(x).then solve the equation P(x)=0. 1.P(x)=x^3+4x^2+x-6 2.P(x)=x^3-6x^2-x+6 3.P(x)=x^3-x^2-x+1 4.P(x)=2x^3-3x^2-3x+2 5.P(x)=x^4-x^3-19x^2+49x-30

Algebra.Com
Question 985474: Factors the polynomial P(x).then solve the equation P(x)=0.
1.P(x)=x^3+4x^2+x-6
2.P(x)=x^3-6x^2-x+6
3.P(x)=x^3-x^2-x+1
4.P(x)=2x^3-3x^2-3x+2
5.P(x)=x^4-x^3-19x^2+49x-30

Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!
5.



Possible rational solutions are ±1, ±2, ±3, ±5, ±6, ±10, ±15, ±30

Try 2

1 | 1  -1 -19  49 -30
  |     1   0 -19  30
    1   0 -19  30   0

So we have factored P(x) as 



Possible rational solutions to the second parenthetical expression
set = 0 are ±1, ±2, ±3, ±5, ±6, ±10, ±15, ±30


Try 2

2 | 1   0 -19  30
  |  2   4 -30
    1   2 -15   0

So we have factored P(x) further as as



Now just factor the trinomial:



x-1=0;  x-2=0;  x+5=0;  x-3=0
  x=1;    x=2     x=-5    x=3

Edwin

RELATED QUESTIONS

Factor the polynomial P(x). Then solve the equation P(x)=0. 1.P(x)=x^3+4x^2+x-6... (answered by ikleyn)
Factor the polynomial P(x). Then solve the equation P(x)=0. 1.P(x)=x^3+4x^2+x-6... (answered by ikleyn)
Factor the polynomial P(x). Then solve the equation P(x)=0. 1.P(x)=x^3+4x^2+x-6... (answered by ikleyn)
use the p over q method and synthetic division to factor the polynomial P(x). then solve... (answered by Boreal,MathLover1)
Given that P(x) = x^4 + ax^3 - x^2 + bx - 12 has factors x-2 and x+1,solve the equation... (answered by greenestamps)
Use p over q method and synthetic division to factor the polynomial P(x). Then solve... (answered by ikleyn)
How would I use the p over q method and synthetic division to factor these polynomials... (answered by tinbar)
Let p(x) be a cubic polynomial. If p(0) = 0, p(1) = 1, p(2) = 2, and p(3) = 3, then... (answered by CPhill,ikleyn,math_tutor2020)
if p(x)=1-x^3 then... (answered by ReadingBoosters)