SOLUTION: Please help me with this mixture word problem. A jewel has five rings, each weighing 18 g, made of an alloy of 10% silver and 90% gold. He decides to melt down the rings and add
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Question 98457This question is from textbook Algebra and Trigonometry
: Please help me with this mixture word problem. A jewel has five rings, each weighing 18 g, made of an alloy of 10% silver and 90% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 75%. How much silver should he add? I'm having a lot of difficulty with setting up and equation for this particular problem. I would be very thankful if you would help me out. Thank you
This question is from textbook Algebra and Trigonometry
Answer by mathslover(157) (Show Source): You can put this solution on YOUR website!
total weight of the rings = 18 * 5 = 90g
total amount of silver = 10/100 *90 = 9g
Total amount of gold in all the 5 rings = 90 -9 =81g
Let the amount of silver added be x grams
total weight of the mixture now = 90 + x
percentage of gold = 81/(90+x) *100
since the percentage of gold now is to be 75
81/(90+x) *100 = 75
81 * 100 = 75 (90+x)
27 * (3 * 25) * 4= 75(90+x)
canceling out 75 on both sided
27* 4 = 90 +x
x = 108 -90
=18g
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