SOLUTION: Hi
there were pears and apples in a box.if 4 pears were taken out there woud be an equal number of pears and apples in the box.if 7 pears were taken out there would be 4/5 as many
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Question 983407: Hi
there were pears and apples in a box.if 4 pears were taken out there woud be an equal number of pears and apples in the box.if 7 pears were taken out there would be 4/5 as many pears as apples in the box.
how many apples were there at first
how many pears were there at first
thank you
Found 2 solutions by mananth, josgarithmetic:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let there be x pears and y apples in a box.
if 4 pears were taken out there woud be an equal number of pears and apples in the box.
x-4 = y
x-y =4...............(1)
if 7 pears were taken out there would be 4/5 as many pears as apples in the box.
x-7 = 4/5 (y)
5(x-7) = 4y
5x-35 =4y
5x-4y =35..............(2)
x-y =4...............(1)
5x-4y =35..............(2)
multiply (1) by -4 we get
-4x+4y=-16
add to (2)
x=19 Number of pears
x-y=4
19-y=4
y=15 Number of apples
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
p pears
a apples
Solve that system for a and p.
Tell if you find trouble doing that.
----
a=15, p=11 p=19
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