Question 980797: A combination lock uses three integers in the combination, and the dial is numbered with integers 0,1,2, and 3. If consecutive numbers in the combination cannot be the same, how many possible combinations are there?
Answer by lmeeks54(111)   (Show Source):
You can put this solution on YOUR website! This is pretty straight forward:
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The first slot can be any of the four available digits, 0, 1, 2, or 3
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The second slot has the same digits available, but you can't repeat the digit from the first slot, so three available choices...
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The third slot is like the second, it has the same four digits on the dial, but one of them is used in the prior setting, so it is unavailable in this slot...
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To compute the number of available combinations to set:
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4 x 3 x 3 = 36 possible combinations
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