SOLUTION: The present ages of a husband and wife are in the ratio of seven to six, and five years ago the ratio was six to five. Find their ages now.

Algebra.Com
Question 972804: The present ages of a husband and wife are in the ratio of seven to six, and five years ago the ratio was six to five. Find their ages now.
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
The present ages of a husband and wife are in the ratio of seven to six,
and five years ago the ratio was six to five.
Find their ages now.
:
let x = the multiplier
then
7x = husband's age now
6x = wife's age now
:
" five years ago the ratio was six to five.
=
cross multiply
6(6x-5) = 5(7x-5)
36x - 30 = 35x - 25
36s - 35x = -25 + 30
x = 5 is the multiplier
therefore
5(7) = 35 is husband's age
and
5(6) = 30 is wife's age
:
:
See if that checks out in the statement
"five years ago the ratio was six to five.
=
=

RELATED QUESTIONS

Could you please help with this problem? The present ages of a husband and wife are in (answered by Alan3354,MathLover1,MathTherapy)
1. Find three consecutive numbers such that the sum of one-fourth the first and one-fifth (answered by checkley75)
a man is six years older than his wife.six years ago the ratio of their ages wa 7:6 find... (answered by ankor@dixie-net.com)
a man is six years older than his wife.six years ago the ratio of their ages wa 7:6 find... (answered by MathLover1,MathTherapy,greenestamps)
The present ages of A and B are as 6:4.Five years ago their ages were in the ratio... (answered by Fombitz)
Five years ago father's age was seven times his sons age. Ten years hence their ages will (answered by nerdybill)
if the present age of a husband and wife are in the ratio of 5:4, what would the ratio of (answered by KMST)
1. presently, the ages of a father and his son are 10x and x years respectively. In 32... (answered by ankor@dixie-net.com)
Five years ago a mother was twice as old as her son in six years time the sum of their... (answered by stanbon)