SOLUTION: Find three consecutive numbers such that the sum of one-fourth the first and one-fifth the second is five less than one-seventh the third.

Question 972802: Find three consecutive numbers such that the sum of one-fourth the first and one-fifth the second is five less than one-seventh the third.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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n, n+1, n+2= three consecutive numbers
.

Multiply by 140.
Subtract (20n+28) from each side.
Divide each side by 43.
The first number is -16.
The second number is -15.
The third number is -14.
.
CHECK:

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