SOLUTION: A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze?

Question 967079: A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze?
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Equation:
anti - anti + anti = anti
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0.3*10 - 0.3*x + 1*x = 0.6*10
0.7x = 0.3*10
x = (3/7)10
x = 4.29 quarts (amt. to remove and replace)
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Cheers,
Stan H.
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