# SOLUTION: A certain creme mixture contains 12 grams of creme A, 18.6 grams of petrolatum, and 30 grams univase. The pharmacist needs to make a 480-gram mixture containing the same ratio of i

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A certain creme mixture contains 12 grams of creme A, 18.6 grams of petrolatum, and 30 grams univase. The pharmacist needs to make a 480-gram mixture containing the same ratio of i      Log On

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 Question 96682: A certain creme mixture contains 12 grams of creme A, 18.6 grams of petrolatum, and 30 grams univase. The pharmacist needs to make a 480-gram mixture containing the same ratio of ingredients. How much of each ingredient should she include?Answer by ankor@dixie-net.com(15646)   (Show Source): You can put this solution on YOUR website!A certain creme mixture contains 12 grams of creme A, 18.6 grams of petrolatum, and 30 grams univase. The pharmacist needs to make a 480-gram mixture containing the same ratio of ingredients. How much of each ingredient should she include? : Here is one way to do it, by proportions : Let the amt of the three ingredients be x, y, and z : Find the original total amt: 12 + 18.6 + 30 = 60.6 : Find x = Cross mult: 60.6x = 12 * 480 60.6x = 5760 x = x = 95.05 : Find y: = 60.6y = 18.6 * 480 60.6y = 8928 y = y = 147.3 : Find z = : you should be able to complete this problem : you can check the amts by adding them all up and seeing if they ~ 480