SOLUTION: A certain creme mixture contains 12 grams of creme A, 18.6 grams of petrolatum, and 30 grams univase. The pharmacist needs to make a 480-gram mixture containing the same ratio of i

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Question 96682: A certain creme mixture contains 12 grams of creme A, 18.6 grams of petrolatum, and 30 grams univase. The pharmacist needs to make a 480-gram mixture containing the same ratio of ingredients. How much of each ingredient should she include?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A certain creme mixture contains 12 grams of creme A, 18.6 grams of petrolatum, and 30 grams univase. The pharmacist needs to make a 480-gram mixture containing the same ratio of ingredients. How much of each ingredient should she
include?
:
Here is one way to do it, by proportions
:
Let the amt of the three ingredients be x, y, and z
:
Find the original total amt: 12 + 18.6 + 30 = 60.6
:
Find x
12%2F60.6 = x%2F480
Cross mult:
60.6x = 12 * 480
60.6x = 5760
x = 5760%2F60.6
x = 95.05
:
Find y:
18.6%2F60.6 = y%2F480
60.6y = 18.6 * 480
60.6y = 8928
y = 8928%2F60.6
y = 147.3
:
Find z
30%2F60.6 = z%2F480
:
you should be able to complete this problem
:
you can check the amts by adding them all up and seeing if they ~ 480