how much water should be added to 28 milliliters of 17% alcohol solution to reduce the concentration to 14%?
In the beginning, 17% of the 28 milliliters of liquid, which is 4.76
milliliters, is pure alcohol. The rest is water.
Then we add x milliliters of water.
Now we have 28+x milliliters of liquid of which the 4.76 milliliters
of pure ancohol is now only 14% of. So,
The 4.76 ml. of pure alcohol = 14% of the 28+x milliliters of liquid.
4.76 = .14(28 + x)
Solve that and get x=6 as the number of milliliters of water to add.
Edwin