SOLUTION: Suppose 9 quarts of a solution that is 95% antifreeze is mixed with 7 quarts of a solution that is 55% antifreeze.
(a) How many quarts of antifreeze are in the resulting mixtu
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Question 948509: Suppose 9 quarts of a solution that is 95% antifreeze is mixed with 7 quarts of a solution that is 55% antifreeze.
(a) How many quarts of antifreeze are in the resulting mixture?
Quarts ___________
(b) What percentage of the resulting mixture is antifreeze?
% ___________
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
9 qts of 95% antifreeze =0.95(9 qts)=8.55 qts antifreeze
7 qts of 55% antifreeze =0.55(7 qts)=3.85 qts antifreeze
The mixture contains 8.55 qts+3.85 qts=12.4 qts antifreeze
ANSWER 1: The resulting mix contains 12.4 qts antifreeze.
There are a total of 9 qts+7 qts=16 qts
(12.4 qts/16 qts)(100%)=77.5%
ANSWER 2: The resulting mix is 77.5% antifreeze.
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