SOLUTION: A 40% solution of fertilizer is to be mixed with a 80% solution of fertilizer in order to get 40 gallons of a 70% solution. How many gallons of the 40% solution and 80% solution sh
Algebra.Com
Question 947949: A 40% solution of fertilizer is to be mixed with a 80% solution of fertilizer in order to get 40 gallons of a 70% solution. How many gallons of the 40% solution and 80% solution should be mixed?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Do it like this one. Only the numbers are different.
-----------
Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use?
================
e = amount of 8%
f = amount of 56%
---
e+ f = 8 (total solution)
8e + 56f = 20*8 (total saline)
---
e+ f = 8
e + 7f = 20
------------ Subtract
-6f = -12
f = 2
e = 6
RELATED QUESTIONS
a 40% solution of fertilizer is to be mixed with a 70% solution of fertilizer in order to (answered by josgarithmetic)
a 20% solution of fertilizer is to be mixed with a 50% solution of fertilizer in order to (answered by fcabanski)
a 10% solution of fertilizer is to be mixed with a 50% solution of fertilizer in order to (answered by mananth)
A 20% solution of fertilizer is to be mixed with a 50% solution of fertilizer in order to (answered by richwmiller)
a 20% solution of fertilizer is to be mixed with a 80% solution of fertilizer in order to (answered by checkley77)
A 20% solution of fertilizer is to be mixed with a 80% solution of fertilizer in order to (answered by KMST)
a 10% solution of fertilizer is to be mixed with a 70% solution of fertilizer in order to (answered by TimothyLamb)
A 10% solution of fertilizer is to be mixed with a 70% solution of fertilizer in order to (answered by josgarithmetic)
A 30% solution of fertilizer is to be mixed with a 70% solution of fertilizer in order to (answered by stanbon)