SOLUTION: A chemist mixes 225 milliliters of a solution that is 39% acid with 25 milliliters of a solution that is 19% acid. A, How many milliliters of acid are in the resulting mixture?

Question 946579: A chemist mixes 225 milliliters of a solution that is 39% acid with 25 milliliters of a solution that is 19% acid.
A, How many milliliters of acid are in the resulting mixture?
B, What percentage of the resulting mixture is acid?

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A chemist mixes 225 milliliters of a solution that is 39% acid with 25 milliliters of a solution that is 19% acid.
:
A, How many milliliters of acid are in the resulting mixture?
The resulting mixture is the sum of two solutions
225 + 25 = 250 ml
:
B, What percentage of the resulting mixture is acid?
let x = the percent of the resulting mixture in decimal form
.39(225) + .19(25) = 250x
87.75 + 4.75 = 250x
92.5 = 250x
x = 92.5/250
x = .37, 37% acid in the resulting mixture
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