SOLUTION: Two planes are 1410 mi apart and are traveling toward each other. One plane is traveling 120 mph faster than the other plane. The planes pass each other in 1.5 h. Find the speed of
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Question 942333: Two planes are 1410 mi apart and are traveling toward each other. One plane is traveling 120 mph faster than the other plane. The planes pass each other in 1.5 h. Find the speed of each plane.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Two planes are 1410 mi apart and are traveling toward each other. One plane is traveling 120 mph faster than the other plane. The planes pass each other in 1.5 h. Find the speed of each plane.
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x=speed of slower plane
x+120=speed of faster plane
travel time*speed=distance(same for both planes)
1.5x+1.5(x+120)=1410
1.5(2x+120)=1410
3x+180=1410
3x=1230
x=410
x+120=530
speed of slower plane=410 mph
speed of faster plane=530 mph
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