SOLUTION: How many liters of a 10% solution of acid should be mixed with 60% solution of acid to obtain 20 liters of 50% solution.
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Question 936652: How many liters of a 10% solution of acid should be mixed with 60% solution of acid to obtain 20 liters of 50% solution.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
x the amount of 60% solution
.60x + .10(20L - x) = .50(20L)
x = .40(20L)/.5 = 16L, the amount of 60% solution
20L - x, the amount of 10% solution
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