SOLUTION: mix a solution that is 50% acid with a solution that is 100% water to make 4L of a solution that is 10% acid. How much of each solution should you use?

Question 928659: mix a solution that is 50% acid with a solution that is 100% water to make 4L of a solution that is 10% acid. How much of each solution should you use?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = liters of 50% acid = liters of 50% water
y = liters of pure water
z = liters of 10% acid = liters of 90% water = 4
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x + y = 4
50x + 100y = 90(x + y)
50x + 100y = 90*4
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put the system of linear equations into standard form
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x + y = 4
50x + 100y = 360
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https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x = liters of 50% acid = 0.8
y = liters of pure water = 3.2
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Solve systems of linear equations up to 6-equations 6-variables:
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