SOLUTION: A metallurgist has one alloy containing 29% aluminum and another containing 51% aluminum. How many pounds of each alloy must he use to make 48 pounds of a third alloy containing 50

Question 928570: A metallurgist has one alloy containing 29% aluminum and another containing 51% aluminum. How many pounds of each alloy must he use to make 48 pounds of a third alloy containing 50% aluminum?
Im stuck after
x+y=48
.29x+.51y=?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = pounds of 29% alloy
y = pounds of 51% alloy
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x + y = 48
29x + 51y = 50*48
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put the system of linear equations into standard form
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x + y = 48
29x + 51y = 2400
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x = pounds of 29% alloy = 2.1818182
y = pounds of 51% alloy = 45.818182
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Solve systems of linear equations up to 6-equations 6-variables:
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