SOLUTION: How many gallons of a 21% acid solution and the 29% acid solution need to be mixed to make 8 gallons of a 26% acid solution?

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Question 927909: How many gallons of a 21% acid solution and the 29% acid solution need to be mixed to make 8 gallons of a 26% acid solution?
Answer by Techpriest(29)   (Show Source): You can put this solution on YOUR website!
Assuming we don't know the gallons of the 21% acid solution, we will express it as x.
Assuming we don't know the gallons of the 29% acid solution, we will express it as y.
In the assumptions, we are able to convey this equation.


We are able to solve it through substitution by finding that y = 8 - x through the subtraction property of equality.
Substitution
Since they are a percent, we will multiply all by 100.
Distribution
Combine Like Terms
Subtraction Property of Equality
Division Property of Equality

Now we know that x is 3, we will plug-in the x for the y to find the value of y.



It takes 3 gallons of a 21% acid solution and 5 gallons of a 29% acid solution to make 8 gallons of a 26% acid solution.
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