SOLUTION: how many liters of 70% of acid solution must be mixed with a 15% acid solution to get 440 L of 60% acid solution?
Algebra.Com
Question 926304: how many liters of 70% of acid solution must be mixed with a 15% acid solution to get 440 L of 60% acid solution?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Do it like this one. Only the numbers are different.
-----------
Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use?
================
e = amount of 8%
f = amount of 56%
---
e+ f = 8 (total solution)
8e + 56f = 20*8 (total saline)
---
e+ f = 8
e + 7f = 20
------------ Subtract
-6f = -12
f = 2
e = 6
RELATED QUESTIONS
How many liters of a 70% acid solution must be mixed with a 25% acid solution to get 270... (answered by Fombitz)
how many liters of a 70% acid solution must be mixed with a 30% acid solution to get 240... (answered by macston)
How many liters of a 70% acid solution must be mixed with a 25% acid solution to get 315... (answered by josgarithmetic)
How many liters of 70% acid solution must be mixed with 10% acid solution to get 480 L of (answered by stanbon)
how many liters of 80% acid solution must be mixed with 15% acid solution to get 455 L of (answered by lwsshak3)
how many liters of a 60% acid solution must be mixed with a 15% acid solution to get 405... (answered by ankor@dixie-net.com)
how many liters of a 60 acid solution must be mixed with 15% acid solution to get 360 l... (answered by josgarithmetic)
how many liters of a 70% acid solution must be mixed with a 15% acid solution to get 385L (answered by Alan3354)
How many liters of a 70% acid solution must be mixed with a 15% acid... (answered by josgarithmetic)