SOLUTION: A chemist wishes to make 3 liters of a 7% acid solution by mixing a 9% acid solution and a 4% acid solution. How many liters of each solution should the chemist use?

Algebra.Com
Question 926059: A chemist wishes to make 3 liters of a 7% acid solution by mixing a 9% acid solution and a 4% acid solution. How many liters of each solution should the chemist use?
Answer by TimothyLamb(4379)   (Show Source): You can put this solution on YOUR website!
x = liters of 9%
y = liters of 4%
---
9x + 4y = 7*3
x + y = 3
---
put the system of linear equations into standard form
---
9x + 4y = 21
x + y = 3
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
answer:
x = liters of 9% = 1.8
y = liters of 4% = 1.2
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php

RELATED QUESTIONS

A chemist wishes to make 3 liters of a 7% acid solution by mixing a 9% acid solution and... (answered by Alan3354)
if a chemist wishes to male 3 liters of a 7% acid solution by mixing a 9% acid and a 4%... (answered by Alan3354)
2. A chemist wishes to make 3 liters of a 7% acid solution by mixing a 9% acid solution... (answered by ewatrrr)
A chemist wishes to make 2 L of an 8% acid solution by mixing a 10% acid solution and a... (answered by nerdybill)
A chemist wants to make 75 liters of 16% acid solution. He is going to make it by mixing... (answered by ankor@dixie-net.com)
A chemist wants to make 40 liters of 22.5% acid solution. She is going to make it by... (answered by nerdybill)
A chemist wants to make 54 mL of a 17% acid solution by mixing a 13% acid solution and an (answered by checkley77)
A chemist wishes to make a 14% acid solution. She has an 8% acid solution and a solution... (answered by josgarithmetic)