SOLUTION: How many pounds of hamburger that costs $1.10 per pound must be mixed with 50 pounds of hamburger that costs $1.80 per pound to make a mixture that costs $1.30 per pound?

Question 92150: How many pounds of hamburger that costs $1.10 per pound must be mixed with 50 pounds of hamburger that costs $1.80 per pound to make a mixture that costs $1.30 per pound?
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=number of pounds of $1.10 hamburger needed
Then 1.10x=value of the $1.10 hamburger
And (1.80)*50=value of the 1.80 hamburger
Also (1.30)(50+x)=value of the final hamburger mixture
Now we know that the total value of the hamburger before the mixture(1.10x+50*(1.80)) has to equal the value of the final hamburger mixture((1.30)(50+x)). So our equation to solve is:
1.10x+50(1.80)=(1.30)(50+x) get rid of parens
1.10x+90=65+1.30x subtract 1.30x and also 90 from both sides
1.10x-1.30x+90-90=1.30x-1.30x+65-90 collect like terms
-0.20x=-25 divide both sides by -0.20
x=125---------------------number of pounds of $1.10 hamburger needed

CK
125($1.10)+50($1.80)=175($1.30)
$137.5+$90=$227.5
$227.5=$227.5
Hope this helps-----ptaylor

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