SOLUTION: how many liters of pure water must be combined with an 18-liter mixture that is
24% acid in order to obtain a mixture that is 15% acid? Your answer may be a
decimal number, but i
Algebra.Com
Question 917346: how many liters of pure water must be combined with an 18-liter mixture that is
24% acid in order to obtain a mixture that is 15% acid? Your answer may be a
decimal number, but it must be exact.
Answer: ________________________________
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
--- percent ---------------- Amount
acid 24 ---------------- 18 liters
water 0 ---------------- x liters
Mixture 15 ---------------- 18 + x liters
24 * 18 + 0 x = 15 ( 18 + x )
432 + 0 x = 270 + 15 x
0 x -15 x = -432 + 270
-15 x = -162
/ -15
x = 10.8 liters water
RELATED QUESTIONS
how many liters of 5% acid should be combined with a 15-liter mixture that is 30% acid... (answered by richwmiller)
A chemist wants to create a solution that is 24% acid. How many liters of a 40% acid... (answered by richwmiller)
A 100 liter barrel of vinegar is 8% acetic acid. Before it can be bottled and used in... (answered by josmiceli)
how many liters of a 20% solution must be mixed with 40 Liters of an 80% solution, in... (answered by lwsshak3)
To the nearest tenth, how much pure acid must be added to 12 liters of a 20% acid... (answered by ptaylor)
How many liters of pure water should be mixed with an 8-L solution of 60% acid to produce (answered by stanbon,richwmiller)
How many liters of pure water should be mixed with a 12 liter solution of 90% acid to... (answered by josgarithmetic)
an automobile director contains 8 liters of solution that 10% is antifreeze. How many... (answered by lwsshak3)
Using the given variable write an equation or inequality that comes from the following... (answered by josmiceli,solver91311)