SOLUTION: Forty gallons of a 60% acid solution is obtained by mixing a 75% solution with a 50% solution. How many gallons of each solution must be used to obtain the desired mixture?

Question 915702: Forty gallons of a 60% acid solution is obtained by mixing a 75% solution with a 50% solution. How many gallons of each solution must be used to obtain the desired mixture?
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
The method here makes sense only if the percents are volume per volume; otherwise, other details might be necessary.

u, volume of 50%
v, volume of 75%

The fraction could be used as a percentage.

, using just sum of the material volume quantities.

Linear system of equations,
RELATED QUESTIONS
Ten gallons of 30% acid solution is obtained by mixing a 20% solution with a 50%... (answered by josmiceli)

Four gallons of a 45% acid solution is obtained by mixing a 90% solution with a 30%... (answered by richwmiller,oberobic,mananth)

Fifty gallons of a 90% alcohol solution is obtained by mixing a 100% solution with a 75%... (answered by checkley77)

please help me solve this problem, Ten gallons of a 30% acid solution is obtained by... (answered by scott8148)

How many gallons of acid must be mixed with 40 gallons of 60% acid solution to get a 75%... (answered by ptaylor)

a lab needs to make 100 gallons of a 18% acid solution by mixing a 12% acid solution with (answered by mananth)

a 70% acid solution is to be mixed with a 40% solution to get 90 gallons of a 50%... (answered by mananth)

A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid solution (answered by checkley79)

A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid solution... (answered by stanbon,josgarithmetic)