SOLUTION: how many liters of 80% acid solution must be mixed with 15% acid solution to get 455 L of a 70% acid solution?
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Question 913425: how many liters of 80% acid solution must be mixed with 15% acid solution to get 455 L of a 70% acid solution?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
how many liters of 80% acid solution must be mixed with 15% acid solution to get 455 L of a 70% acid solution?
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let x=amt of 80% solution to mix
455-x=amt of 15% solution to mix
80%x+15%(455-x)=70%*455
.80x+68.25-.15x=318.5
0.65x=250.25
x=385
455-x=70
amt of 80% solution to mix=385 liters
amt of 15% solution to mix=70 liters
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