SOLUTION: A radiator contains 8 liters of 40% antifreeze solution. How many liters of pure antifreeze must be added to obtain a 50% solution?

Question 907631: A radiator contains 8 liters of 40% antifreeze solution. How many liters of pure antifreeze must be added to obtain a 50% solution?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
We have 8 liter of 40% antifreeze
We want to add some 100% antifreeze to make 50% antifreeze
1*x+0.4*8=0.5(8+x)
1*x+3.2=4+0.5x
1x-0.5x=4-3.2
0.5x=0.8
x=1.6 liter at 100% (1.6) is added to 8 liter at 40%(3.2) to make 50% of 9.6 liter(4.8)
check
1*1.6+0.4*8=0.5(8+1.6)
1.6+3.2=0.5(9.6)
4.8=4.8
ok

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