SOLUTION: How many liters of a 60% acid solution must be mixed with a 25% acid solution to get 315L of a 50% acid solution?
Algebra.Com
Question 907385: How many liters of a 60% acid solution must be mixed with a 25% acid solution to get 315L of a 50% acid solution?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
x 60% amount
.60x + .25(315L - x) = .50(315L)
x = .25(315L)/.35
RELATED QUESTIONS
How many liters of a 60% acid solution must be mixed with 20% acid solution to get 320... (answered by Alan3354)
How many liters of a 50% acid solution must be mixed with a 25% acid solution to get 225... (answered by richwmiller)
how many liters of a 60% acid solution must be mixed with a 10% acid solution to get 400... (answered by checkley79)
how many liters of a 60% acid solution must be mixed with a 15% acid solution to get 405... (answered by ankor@dixie-net.com)
How many liters of a 70% acid solution must be mixed with a 25% acid solution to get 270... (answered by Fombitz)
How many liters of a 70% acid solution must be mixed with a 25% acid solution to get 315... (answered by josgarithmetic)
How many liters of 60% acid solution must be mixed with a 30% acid solution to get 240 L... (answered by ewatrrr)
how many liters of a 60 acid solution must be mixed with 15% acid solution to get 360 l... (answered by josgarithmetic)
how many liters of a 70% acid solution must be mixed with a 30% acid solution to get 400... (answered by josgarithmetic)