SOLUTION: A tank contains 10L of 25% solution of alcohol. How much must be taken from the tank to be replaced by a 5% solution of alcohol so that the vessel will now contain a 10% solution

Question 905723: A tank contains 10L of 25% solution of alcohol. How much must be taken from the tank to be replaced by a 5% solution of alcohol so that the vessel will now contain a 10% solution of alcohol?
Found 2 solutions by josgarithmetic, lwsshak3:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The concept is exactly the same as this:

Drain and Replace: Radiator Antifreeze Mixture

The algebra and arithmetic is what is important; NOT the identity of the substance dissolved.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
A tank contains 10L of 25% solution of alcohol. How much must be taken from the tank to be replaced by a 5% solution of alcohol so that the vessel will now contain a 10% solution of alcohol?
***
let x=amt of 25% solution to be taken out and replaced by a 5% solution.
25%(10-x)+5%x=10%*10
2.5-.25x+.05x=1
.20x=1.5
x=7.5
amt of 25% solution to be taken out and replaced by a 5% solution. 7.5L
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